1989 Virginia Slims of Nashville – Doubles

Jenny Byrne and Janine Tremelling were the defending champions, but none competed this year.

Doubles
1989 Virginia Slims of Nashville
Final
ChampionsNetherlands Manon Bollegraf
United States Meredith McGrath
Runners-upSoviet Union Natalia Medvedeva
Soviet Union Leila Meskhi
Score1–6, 7–6(7–5), 7–6(7–4)
Details
Draw16
Seeds4
Events
Singles Doubles
← 1988 · Virginia Slims of Nashville · 1990 →

Manon Bollegraf and Meredith McGrath won the title by defeating Natalia Medvedeva and Leila Meskhi 1–6, 7–6(7–5), 7–6(7–4) in the final.[1]

Seeds

edit

Draw

edit

Draw

edit
First round Quarterfinals Semifinals Final
1   E Smylie
  W Turnbull
6 7
  H Kelesi
  C Porwik
0 5 1   E Smylie
  W Turnbull
6 6
  J Pospíšilová
  H Witvoet
3 6 5   K Foxworth
  T Whittington
1 4
  K Foxworth
  T Whittington
6 4 7 1   E Smylie
  W Turnbull
4 6
4   ML Daniels
  W White
3 6 7   N Medvedeva
  L Meskhi
6 7
  P Hy
  E Inoue
6 3 6 4   ML Daniels
  W White
2 4
  N Medvedeva
  L Meskhi
6 6   N Medvedeva
  L Meskhi
6 6
  L Bartlett
  F Labat
4 1   N Medvedeva
  L Meskhi
6 65 64
  Ca MacGregor
  Cy MacGregor
6 7 2   M Bollegraf
  M McGrath
1 77 77
  LA Eldredge
  M Norwood
4 6   Ca MacGregor
  Cy MacGregor
3 6 7
  A Keller
  L Spadea
7 6   A Keller
  L Spadea
6 3 6
3   L Allen
  J Hetherington
6 3   Ca MacGregor
  Cy MacGregor
2 4
  H Cioffi
  J Thomas
3 6 2   M Bollegraf
  M McGrath
6 6
  P Barg
  P Louie Harper
6 7   P Barg
  P Louie Harper
2 6
  S Martin
  S Sloane
3 0 2   M Bollegraf
  M McGrath
6 7
2   M Bollegraf
  M McGrath
6 6

References

edit
  1. ^ John Barrett, ed. (1990). The International Tennis Federation : World of Tennis 1990. London: Willow Books. pp. 163, 165, 206. ISBN 9780002183550.
edit