1892 Rhode Island gubernatorial election

The 1892 Rhode Island gubernatorial election was held on April 6, 1892. Republican nominee Daniel Russell Brown defeated Democratic nominee William T. C. Wardwell with 50.22% of the vote.

1892 Rhode Island gubernatorial election

← 1891 April 6, 1892 1893 →
 
Nominee Daniel Russell Brown William T. C. Wardwell
Party Republican Democratic
Popular vote 27,461 25,433
Percentage 50.22% 46.51%

County results
Brown:      40–50%      50–60%
Wardwell:      40–50%

Governor before election

Herbert W. Ladd
Republican

Elected Governor

Daniel Russell Brown
Republican

General election

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Candidates

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Major party candidates

  • Daniel Russell Brown, Republican
  • William T. C. Wardwell, Democratic

Other candidates

  • Alexander Gilbert, Prohibition
  • Franklin E. Burton, People's

Results

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1892 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Daniel Russell Brown 27,461 50.22%
Democratic William T. C. Wardwell 25,433 46.51%
Prohibition Alexander Gilbert 1,598 2.92%
Populist Franklin E. Burton 187 0.34%
Majority 2,028
Turnout
Republican hold Swing

References

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  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 24, 2020.