1845 New Hampshire gubernatorial election

The 1845 New Hampshire gubernatorial election was held on 11 March 1845 in order to elect the governor of New Hampshire. Incumbent Democratic governor John Hardy Steele won re-election against Whig nominee and former member of the New Hampshire House of Representatives Anthony Colby and Liberty nominee Daniel Hoit in a rematch of the previous election.[1]

1845 New Hampshire gubernatorial election

← 1844 11 March 1845 1846 →
 
Nominee John Hardy Steele Anthony Colby Daniel Hoit
Party Democratic Whig Liberty
Popular vote 23,406 15,585 5,786
Percentage 51.14% 34.05% 12.64%

County results
Steele:      40–50%      50–60%      60–70%      70–80%
Colby:      40–50%

Governor before election

John Hardy Steele
Democratic

Elected Governor

John Hardy Steele
Democratic

General election

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On election day, 11 March 1845, incumbent Democratic governor John Hardy Steele won re-election by a margin of 7,821 votes against his foremost opponent Whig nominee Anthony Colby, thereby retaining Democratic control over the office of governor. Steele was sworn in for his second term on 4 June 1845.[2]

Results

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New Hampshire gubernatorial election, 1845
Party Candidate Votes %
Democratic John Hardy Steele (incumbent) 23,406 51.14
Whig Anthony Colby 15,585 34.05
Liberty Daniel Hoit 5,786 12.64
Scattering 988 2.17
Total votes 45,765 100.00
Democratic hold

References

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  1. ^ "John Hardy Steele". National Governors Association. Retrieved 2 April 2024.
  2. ^ "NH Governor". ourcampaigns.com. 3 June 2005. Retrieved 2 April 2024.