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December 25

Modular equation

What is the most efficient way to solve for a, in equations of the form (2^a) == 3^b (mod c), b and c coprime? 70.190.182.236 (talk) 19:43, 25 December 2014 (UTC)[reply]

And I know that this is a discrete logarithm problem, but does the specific form of 2^a / 3^b have a better solution? 70.190.182.236 (talk) 22:10, 25 December 2014 (UTC)[reply]