Talk:Supercommutative algebra

Latest comment: 6 months ago by 67.198.37.16 in topic Supercommutative vs. anticommutative

Definition with 2-torsion

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I notice that R.e.b. made a correction to this article sometime ago regarding the square of odd elements. With the present definition we have

 

for all odd x. If there is no 2-torsion this implies that

 .

However, it seems to be an crucial fact when dealing with commutative superalgebras that the odd elements square to zero. In all of the references I can find, authors either (implicitly or explicitly) assume that 2 is invertible or that there is no 2-torsion, or they explicitly require that   for all odd x. I may edit the article to this effect, but I'm interested in what others have to say. -- Fropuff (talk) 22:03, 7 February 2008 (UTC)Reply

Actually, the more I think about, modifying the definition of supercommutative to insist that   for all odd x seems like the wrong thing to do. It would no longer be true that a superalgebra is commutative iff it is equal to its opposite, or to its supercenter, or iff the supercommutator vanished identically. I guess the correct thing to do is simply assume that 2 is invertible whenever necessary (or at least assume there is no 2-torsion). -- Fropuff (talk) 08:26, 8 February 2008 (UTC)Reply

Yes; Bourbaki distinguishes between anticommutative and alternating algebras, and it seems to me (on the surface) to be exactly this distinction. —Quondum 06:31, 18 December 2016 (UTC)Reply

Supercommutative vs. anticommutative

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This article describes essentially what Bourbaki defines as an anticommutive algebra. There is a subtle distinction between between an anticommutative algebra (defined as Z-graded with the sign-changing property as given in the article with |x| interpreted as the Z-grading) and a supercommutative algebra (defined as Z2-graded): an anticommutative algebra is necessarily also Z2-graded and hence also a supercommutative algebra, but the converse seems to be false, because a Z2-graded algebra need not be amenable to Z-grading. Thus, I would expect supercommutative algebras to exist that are not classifiable as anticommutative algebras. —Quondum 06:50, 18 December 2016 (UTC)Reply

Currently anticommutative algebra is a redirect back to this article, and no explicit definition is given, for what that is, or how a Z-grading might arise. 67.198.37.16 (talk) 19:10, 24 May 2024 (UTC)Reply