Talk:Rice–Shapiro theorem
This article is rated Stub-class on Wikipedia's content assessment scale. It is of interest to the following WikiProjects: | |||||||||||||||||||||||||||||||||||||||||
|
Assessment
editI'm the page author and I've assessed it as importance=Low (it's a relatively obscure topic, even if it is a relatively important theorem in computability theory. --Blaisorblade (talk) 20:19, 16 July 2008 (UTC)
Stewart Shapiro
editThere are various Shapiro, and I just guessed it was Stewart Shapiro the one involved with this theorem; there is {{fact}} (i.e. [citation needed]) about this in the page, but I wanted to make the doubt clear. --Blaisorblade (talk) 20:19, 16 July 2008 (UTC)
Duplicate
editAs far as I could understand, this page explains the Rice's Theorem, which (the other) page is more detailed. Hence, I think this page could be deleted and redirect to Rice's Theorem one. --Guiraldelli (talk) 15:13, 8 September 2015 (UTC)
Saved paragraph from article
editI moved the following paragraph from the article here for discussion as it makes no sense: (a) the set is a set of functions and has no notion of recursively enumerability and (b) where is an integer but denotes a set of functions. Martin Ziegler (talk) 00:11, 3 March 2017 (UTC)
In general, one can obtain the following statement: The set is recursively enumerable iff the following two conditions hold:
(a) is recursively enumerable;
(b) iff a finite function such that extends where is the canonical index of .