Suez Township is located in Mercer County, Illinois. As of the 2010 census, its population was 595 and it contained 277 housing units.[2] Suez Township changed its name from Palmyra Township sometime before 1921.
Suez Township | |
|---|---|
Township | |
 Location in Mercer County | |
 Mercer County's location in Illinois | |
| Country | United States |
| State | Illinois |
| County | Mercer |
| Established | November 8, 1853 |
| Area | |
• Total | 37.11 sq mi (96.1 km2) |
| • Land | 37.11 sq mi (96.1 km2) |
| • Water | 0 sq mi (0 km2) 0% |
| Population (2010) | |
• Estimate (2016)[1] | 567 |
| • Density | 16/sq mi (6/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code | 17-131-73339 |
Geography
editAccording to the 2010 census, the township has a total area of 37.11 square miles (96.1 km2), all land.[2]
Demographics
edit| Census | Pop. | Note | %± |
|---|---|---|---|
| 2016 (est.) | 567 | [1] | |
| U.S. Decennial Census[3] | |||
References
edit- ^ a b "Population and Housing Unit Estimates". Retrieved June 9, 2017.
- ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 28, 2013.
- ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.
External links
edit41°06′44″N 90°36′29″W / 41.11222°N 90.60806°W
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