2019 Open Harmonie mutuelle – Doubles

Sander Arends and Tristan-Samuel Weissborn were the defending champions[1] but lost in the semifinals to Jonathan Eysseric and Antonio Šančić.

Doubles
2019 Open Harmonie mutuelle
Final
ChampionsIsrael Jonathan Erlich
France Fabrice Martin
Runners-upFrance Jonathan Eysseric
Croatia Antonio Šančić
Score7–6(7–2), 7–6(7–2)
Events
Singles Doubles
← 2018 · Open Harmonie mutuelle · 2022 →

Jonathan Erlich and Fabrice Martin won the title after defeating Eysseric and Šančić 7–6(7–2), 7–6(7–2) in the final.

Seeds

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Draw

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First round Quarterfinals Semifinals Final
1   P Oswald
  L Paes
6 2 [8]
  J Cerretani
  M-A Hüsler
4 6 [10]   J Cerretani
  M-A Hüsler
4 4
  LD Martínez
  G Oliveira
62 4 ITF   A Artuñedo
  S Martos Gornés
6 6
ITF   A Artuñedo
  S Martos Gornés
77 6 ITF   A Artuñedo
  S Martos Gornés
3 4
4   J Erlich
  F Martin
6 77 4   J Erlich
  F Martin
6 6
  A Vasilevski
  A Vavassori
3 64 4   J Erlich
  F Martin
78 67 [10]
  R Junaid
  D Pel
6 6   R Junaid
  D Pel
66 79 [6]
WC   E Furness
  M Guinard
4 2 4   J Erlich
  F Martin
77 77
WC   Q Halys
  G Jacq
63 62   J Eysseric
  A Šančić
62 62
  S Arends
  T-S Weissborn
77 77   S Arends
  T-S Weissborn
6 77
ITF   D Added
  A Olivetti
64 6 [10] ITF   D Added
  A Olivetti
4 65
3   R Galloway
  N Lammons
77 4 [8]   S Arends
  T-S Weissborn
3 5
  J Eysseric
  A Šančić
6 6   J Eysseric
  A Šančić
6 7
  S Stakhovsky
  S Walków
3 1   J Eysseric
  A Šančić
77 6
WC   M Martineau
  C Moutet
4 4 2   R Arneodo
  H Nys
64 4
2   R Arneodo
  H Nys
6 6

References

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  1. ^ "Tristan-Samuel Weissborn holt Doppeltitel in St. Brieuc". www.spox.com.
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