1998 Boston Cup – Doubles

Lisa Raymond and Rennae Stubbs won in the final 6–4, 6–4 against Mariaan de Swardt and Mary Joe Fernández.

Doubles
1998 Boston Cup
Final
ChampionsUnited States Lisa Raymond
Australia Rennae Stubbs
Runners-upSouth Africa Mariaan de Swardt
United States Mary Joe Fernández
Score6–4, 6–4
Events
Singles Doubles
← 1997 · Boston Cup · 1999 →

Seeds

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Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1.   Lisa Raymond /   Rennae Stubbs (champions)
  2.   Naoko Kijimuta /   Nana Miyagi (first round)
  3.   Kristine Kunce /   Corina Morariu (first round)
  4.   Amanda Coetzer /   Barbara Schett (first round)

Draw

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First round Quarterfinals Semifinals Final
1   L Raymond
  R Stubbs
6 6  
    E deLone
  S-T Wang
3 1   1   L Raymond
  R Stubbs
6 6  
    N de Villiers
  L McShea
6 1 4     S Farina
  A Huber
4 3  
    S Farina
  A Huber
1 6 6 1   L Raymond
  R Stubbs
7 6  
3   K Kunce
  C Morariu
2 2   Q   C Black
  I Selyutina
6 1  
Q   C Black
  I Selyutina
6 6   Q   C Black
  I Selyutina
6 4 6
    A Ellwood
  T Musgrave
w/o         A Ellwood
  T Musgrave
2 6 2
    O Barabanschikova
  E Likhovtseva
      1   Lisa Raymond
  Rennae Stubbs
6 6  
    L Horn
  M Paz
4 3       Mariaan de Swardt
  Mary Joe Fernández
4 4  
    R McQuillan
  N Pratt
6 6       R McQuillan
  N Pratt
3 3  
    C Cristea
  R Dragomir
1 7 6     C Cristea
  R Dragomir
6 6  
4   A Coetzer
  B Schett
6 6 2     C Cristea
  R Dragomir
3 7 4
    K Freye
  Y Yoshida
6 6       M de Swardt
  M J Fernández
6 5 6
WC   S Kleinová
  B Rippner
2 1       K Freye
  Y Yoshida
3 3  
    M de Swardt
  M J Fernández
6 7       M de Swardt
  M J Fernández
6 6  
2   N Kijimuta
  N Miyagi
1 6  
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