The 1836 United States presidential election in Louisiana took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
|
Louisiana voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Louisiana by a narrow margin of 3.48%.
Results
edit1836 United States presidential election in Louisiana[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 3,842 | 51.74% | 5 | |
Whig | Hugh White | 3,583 | 48.26% | 0 | |
Totals | 7,425 | 100.0% | 5 |
See also
editReferences
edit- ^ "1836 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved August 4, 2012.