The 1836 United States presidential election in Connecticut took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
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 County Results
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Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a narrow margin of 1.3%.
As a result of his win, Van Buren also became the first Democratic presidential candidate to carry Connecticut.
Results
edit| 1836 United States presidential election in Connecticut[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren | 19,294 | 50.65% | 8 | |
| Whig | William Henry Harrison | 18,799 | 49.35% | 0 | |
| Totals | 38,093 | 100.0% | 8 | ||
See also
editReferences
edit- ^ "1836 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved August 4, 2012.
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