The 1826 Maryland gubernatorial election was held on 2 January 1826 in order to elect the Governor of Maryland. Democratic-Republican nominee and incumbent member of the U.S. House of Representatives from Maryland's 2nd district Joseph Kent was elected by the Maryland General Assembly against candidates William Tyler and Thomas H. Carroll.[1]
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General election
editOn election day, 2 January 1826, Democratic-Republican nominee Joseph Kent was elected by the Maryland General Assembly, thereby retaining Democratic-Republican control over the office of governor. Kent was sworn in as the 19th Governor of Maryland on 9 January 1826.[2]
Results
edit| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Joseph Kent | 59 | 65.56 | |
| William Tyler | 30 | 33.33 | ||
| Thomas H. Carroll | 1 | 1.11 | ||
| Total votes | 90 | 100.00 | ||
| Democratic-Republican hold | ||||
References
edit- ^ "Joseph Kent". National Governors Association. Retrieved 27 April 2024.
- ^ "MD Governor". ourcampaigns.com. 28 March 2005. Retrieved 27 April 2024.