The 1816 United States presidential election in Rhode Island took place as part of the 1816 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for president and vice president.
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Rhode Island voted for the Democratic-Republican candidate, James Monroe. Monroe won Rhode Island by a margin of 100.00%. Because the Federalist challenger in the nation, Rufus King, was not on the ballot.
Results
edit| 1816 United States presidential election in Rhode Island[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | James Monroe | 1,236 | 100.00% | 4 | |
| Federalist | Rufus King (not on ballot) | — | — | 0 | |
| Totals | 1,236 | 100.0% | 4 | ||
See also
editReferences
edit- ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved 2024-08-31.