San Pedro Bay (Philippines)

(Redirected from San Pedro Bay, Leyte)

San Pedro Bay is a bay in the Philippines, at the northwest end of Leyte Gulf. It measures about 15 kilometres (9.3 mi; 8.1 nmi) east to west and 20 kilometres (12 mi; 11 nmi) north to south.[1] The bay is bounded by two islands, by Samar the north and east and by Leyte on the east. It is connected by San Juanico Strait to Carigara Bay, an arm of the Samar Sea. The largest city on the bay is Tacloban City, the capital of the province of Leyte in the administrative region of Eastern Visayas.

San Pedro Bay
The Cancabato Bay, an extension of San Pedro Bay in Tacloban
San Pedro Bay is located in Visayas
San Pedro Bay
San Pedro Bay
Location within the Philippines
San Pedro Bay is located in Philippines
San Pedro Bay
San Pedro Bay
San Pedro Bay (Philippines)
LocationEastern Visayas, Philippines
Coordinates11°10′36.84″N 125°6′28.08″E / 11.1769000°N 125.1078000°E / 11.1769000; 125.1078000
Typebay
Part ofLeyte Gulf
Settlements

During World War II, the bay was part of a large United States Navy base, the Leyte-Samar Naval Base.

References

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  1. ^ PacificWrecks.com. "Pacific Wrecks - San Pedro Bay, Leyte Province, Philippines". pacificwrecks.com. Retrieved 2024-11-16.