1893 United States House of Representatives elections
(Redirected from 1893 Rhode Island's 2nd congressional district special election)
There were seven elections in 1893 for United States House of Representatives in the 53rd United States Congress. There were no special elections that year for the 52nd United States Congress, which ended March 3, 1893.
List of elections
editElections are listed by date and district.
| District | Incumbent | This race | |||
|---|---|---|---|---|---|
| Member | Party | First elected | Results | Candidates | |
| Massachusetts 7 | Henry Cabot Lodge | Republican | 1886 | Incumbent member-elect resigned during previous congress to become U.S. senator. New member elected April 25, 1893. Democratic gain. |
|
| Pennsylvania 8 | William Mutchler | Democratic | 1874 1876 (retired) 1880 1884 (retired) 1888 |
Incumbent died June 23, 1893. New member elected August 7, 1893. Democratic hold. |
|
| Wisconsin 4 | John L. Mitchell | Democratic | 1890 | Incumbent member-elect resigned during previous congress to become U.S. senator. New member elected April 4, 1893. Democratic hold.[1] |
|
| Michigan 1 | J. Logan Chipman | Democratic | 1886 | Incumbent died August 17, 1893. New member December 4, 1893. Democratic hold. |
|
| Ohio 10 | William H. Enochs | Republican | 1890 | Incumbent died July 13, 1893. New member December 4, 1893. Republican hold. |
|
| Pennsylvania 2 | Charles O'Neill | Republican | 1862 1870 (lost) 1872 |
Incumbent died November 25, 1893. New member December 19, 1893. Republican hold. |
|
See also
editReferences
edit- ^ "Wisconsin U.S. House Election Results" (PDF). Humphrey Institute of Public Affairs. Archived from the original (PDF) on April 5, 2012. Retrieved March 8, 2022 – via Wayback Machine.
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