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1788–89 United States presidential election in Pennsylvania

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Main article: 1788–89 United States presidential election

The 1788–89 United States presidential election in Pennsylvania took place on January 7, 1789, as part of the 1788–89 United States presidential election to elect the first President. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.

1788–89 United States presidential election in Pennsylvania
January 7, 1789 1792 →
 
Nominee George Washington John Adams John Hancock
Party Independent Federalist Federalist
Home state Virginia Massachusetts Massachusetts
Electoral vote 10 8 2
Popular vote 7,383 – –
Percentage 100.00% – –
President before election

Office established

Elected President

George Washington
Independent

Pennsylvania unanimously voted for nonpartisan candidate and commander-in-chief of the Continental Army, George Washington. The total vote is composed of 6,711 for Federalist electors, known as the Lancaster Ticket, and 672 for Anti-Federalist electors, known as the Harrisburg Ticket, all of whom were supportive of Washington.[1]

Results

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1788-1789 United States presidential election in Pennsylvania[1]
Party Candidate Votes Percentage Electoral votes
Independent George Washington 7,383 100.00% 15
Totals 7,383 100.00% 15

See also

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References

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  1. ^ a b "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 16, 2024.


   

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